2(x+[x+1])=2(x+1)-2

Solution for 2(x+[x+1])=2(x+1)-2 equation:

Simplifying
2(x + [x + 1]) = 2(x + 1) + -2

Reorder the terms:
2(x + [1 + x]) = 2(x + 1) + -2

Remove brackets around [1 + x]
2(x + 1 + x) = 2(x + 1) + -2

Reorder the terms:
2(1 + x + x) = 2(x + 1) + -2

Combine like terms: x + x = 2x
2(1 + 2x) = 2(x + 1) + -2
(1 * 2 + 2x * 2) = 2(x + 1) + -2
(2 + 4x) = 2(x + 1) + -2

Reorder the terms:
2 + 4x = 2(1 + x) + -2
2 + 4x = (1 * 2 + x * 2) + -2
2 + 4x = (2 + 2x) + -2

Reorder the terms:
2 + 4x = 2 + -2 + 2x

Combine like terms: 2 + -2 = 0
2 + 4x = 0 + 2x
2 + 4x = 2x

Solving
2 + 4x = 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
2 + 4x + -2x = 2x + -2x

Combine like terms: 4x + -2x = 2x
2 + 2x = 2x + -2x

Combine like terms: 2x + -2x = 0
2 + 2x = 0

Add '-2' to each side of the equation.
2 + -2 + 2x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2x = 0 + -2
2x = 0 + -2

Combine like terms: 0 + -2 = -2
2x = -2

Divide each side by '2'.
x = -1

Simplifying
x = -1